Count vowels in a file and order by count descending

$ cat vowelfile
this
that
these

$ grep -io [aeiou] vowelfile | uniq -c | sort -rk1
2 e
1 i
1 a

This has three parts:

grep -io
-i ignores the case and -o prints just the part of the string it matches. So it will just list a, e, i, o or u instead of printing the complete line with vowel.

$ grep -io [aeiou] vowelfile
i
a
e
e

uniq -c
Counts the number of unique lines in the grep output.
$ grep -io [aeiou] vowelfile | uniq -c
1 i
1 a
2 e

sort -rk1
sort with option -r reverses the default sort order, which is ascending. By default sort is on the entire line. Option -k allows us to specify the field number to sort on. In the example the first field is the count and the second field is the vowel.


And to get the total counts of the vowel:
grep -io [aeiou] vowelfile | wc -l
wc with -l does the count on lines

Took the basic code from here
http://www.geekinterview.com/question_details/55489