Use searched pattern in substitution

Sometimes we want to search for a pattern and use that pattern in replace as well. Like the substitution is an extension of what we already have in the file.

E.g. append all employee ages with 'years'

emp_name:Jane
emp_age:25
emp_name:John
emp_age:22
emp_name:Mary
emp_age:30
emp_name:Natalie
emp_age:29
other data here

Command

:%s/\(emp_age.*\)/\1 years/g

Breaking it up -

emp_name:Jane

%s - apply thru out the file
\( and \) - escape the parentheses 
(emp_age.*) - consider it a group
\1 - escape 1; 1 means the first pattern, in our case it's the only one
\1 years -  use the first pattern and append years to it
g - replace multiple occurrences on the same line

Output

emp_name:Jane
emp_age:25 years
emp_name:John
emp_age:22 years
emp_name:Mary
emp_age:30 years
emp_name:Natalie
emp_age:29 years
other data here

While I was typing this up, I thought let me try using a second pattern as well.

:%s/\(emp_age.*\)\(years\)/\1- \2/g 

If we run this in the above output we get

emp_name:Jane
emp_age:25 - years
emp_name:John
emp_age:22 - years
emp_name:Mary
emp_age:30 - years
emp_name:Natalie
emp_age:29 - years
other data here

Hope this helps.

NVL equivalent in Unix

Sometimes, we want to assign an alternate value to a variable if it were null. I recently found that it has a one liner in Unix.

var1=${new_var1:-$default_var1}

 Which means if $new_var1 is not null, use it else use the $default_var1.